By Raymond A. Serway, Chris Vuille

For Chapters 1-30, this handbook offers solutions to each a number of selection query, solutions to even numbered conceptual difficulties, solutions to even numbered difficulties, and specific suggestions to each homework challenge within the booklet.

**Read or Download Instructor's Solutions Manual for College Physics (9th Edition) PDF**

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**Example text**

Choice (c). A projectile has constant horizontal velocity. Thus, if the runner throws the ball straight up into the air, the ball maintains the horizontal velocity it had before it was thrown (that is, the velocity of the runner). In the runner’s frame of reference, the ball appears to go straight upward and come straight downward. To a stationary observer, the ball follows a parabolic trajectory, moving with the same horizontal velocity as the runner and staying above the runner’s hand. 7. Choice (b).

5 m, as found in part (c) above. 95 s (a) a= (b) From a = Δv Δt , the required time is Δt = (c) Yes. For uniform acceleration, the change in velocity ∆v generated in time ∆t is given by Δv = a ( Δt ). From this, it is seen that doubling the length of the time interval ∆t will always double the change in velocity ∆v. 00 km. 800 km runway. 35 33 We choose x = 0 and t = 0 at the location of Sue’s car when she ﬁrst spots the van and applies the brakes. 0 m s. 00 m s 2. 00 m s , and its constant acceleration is aV = 0.

5. indd 50 Whether on Earth or the Moon, a golf ball is in free fall with a constant downward acceleration of magnitude determined by local gravity from the time it leaves the tee until it strikes the ground or other object. Thus, the vertical component of velocity is constantly changing while the horizontal component of velocity is constant. Note that the speed (or magnitude of the velocity) 10/13/10 10:24:22 AM Vectors and Two-Dimensional Motion 51 v = v = vx2 + vy2 will change in time since vy changes in time.